How to Size a Hydraulic Oil Tank
Size a hydraulic oil tank with a system volume balance, cylinder displacement, accumulator demand, drainback, thermal allowance, and operating-level checks.
Size a hydraulic oil tank by calculating the greatest and smallest oil quantity it must contain across the system's operating states. Then provide a permitted liquid-level range that covers those states while preserving inlet conditions, headspace, fluid management, and thermal performance. Pump flow alone does not establish the required capacity.
The essential calculation is a volume balance: oil transferred into cylinders, accumulators, and changing line inventories leaves the reservoir, while net return raises its level. This guide develops that balance, includes an original worked example, and connects the result to a preliminary tank geometry. It provides a design record for review, not a finished fabrication drawing or a universal tank-size rule.
Índice
- Define the calculation boundary and reference state
- Calculate cylinder-related inventory changes
- Add accumulators and changing line inventory
- Build a state table instead of adding every maximum
- Convert the result into fill levels and tank geometry
- Check air release, return flow, and inlet performance
- Separate thermal capacity from continuous cooling
- Record assumptions and verify the design
- Preguntas frecuentes
Define the calculation boundary and reference state
Draw a boundary around the complete fluid system. Identify the reservoir, actuators, accumulators, lines, valves, coolers, filters, and any other volumes that can change their oil inventory. Separate permanently filled spaces from spaces whose contents vary during operation.
Choose a reference state and temperature condition. State actuator positions, accumulator oil condition, line filling, and any relevant isolation or control state. Define V0 as the liquid quantity in the reservoir at that reference state.
Use a consistent sign convention. In this article, positive ΔVout means a net transfer of oil from the reservoir to the rest of the system. The reservoir quantity at a state is:
Vtank = V0 − ΔVout + ΔVthermal
Here ΔVthermal represents the net thermal-volume correction assigned to the tank balance under the stated assumptions. Other effects may need separate terms in a detailed model. Do not add thermal allowance again if it is already included in a measured state quantity.
Oil continuously circulating through a pump and returning to the tank does not accumulate outside the tank indefinitely. Flow multiplied by total running time is therefore not the same as required inventory. See basic hydraulic system design for the system boundary and operating-sequence context.

Calculate cylinder-related inventory changes
For a conventional single-rod, double-acting cylinder, extension fills the cap-end chamber while oil leaves the rod-end chamber. If both flows communicate with the same reservoir through the normal open circuit, the net withdrawal is the difference between those swept volumes.
With bore D, rod diameter d, and travel S:
Cap-end swept volume = πD²S/4
Rod-end swept volume = π(D² − d²)S/4
Net reservoir withdrawal on extension = πd²S/4
These are geometric relationships with leakage, compressibility, hose expansion, and other effects ignored. Retraction reverses this inventory change under the same circuit assumptions. The reservoir level falls during extension and rises during retraction.
For an invented cylinder with D = 80 mm, d = 45 mm, and S = 600 mm, use meters in the formulas and multiply cubic meters by 1,000 to obtain liters. The cap end takes approximately 3.016 L; the rod end returns approximately 2.062 L. The net withdrawal is approximately 0.954 L.
It would be incorrect to count the full 3.016 L as the reservoir decrease while ignoring the simultaneous return. Two such cylinders extending together withdraw approximately 1.909 L net. The area definitions are explained in pressure, force, and area.
A single-acting actuator can have a different balance because the other side may not return hydraulic oil to the same reservoir during extension. Use its actual effective swept volume and connections. Telescopic, regenerative, closed-circuit, and interconnected arrangements require their own circuit-based accounting; do not transfer the simple example blindly.

Add accumulators and changing line inventory
An accumulator can withdraw oil during charging and return it during discharge. Use the change in actual oil content between the relevant operating states. Its nominal vessel or gas volume is not automatically the oil exchange volume.
HYDAC's accumulator FAQ explicitly distinguishes nominal gas volume from the amount of fluid available under particular pressure conditions. Obtain an approved calculation or supplier value for the application, including the relevant temperature and operating assumptions. This article does not provide a charging procedure. HYDAC accumulator volume explanation.
For lines, distinguish initial filling from normal cycling and shutdown drainback. A line that remains full contributes to total purchased oil but may contribute no normal inventory swing. A line that drains into the tank can increase the shutdown level.
Also identify auxiliary supplies, case drains, flushing circuits, and external sources or destinations. A flow returning from another reservoir changes the balance differently from recirculation within the same system.
Review control and isolation states using the actual circuit. The overview in how a hydraulic system works helps organize the question, but the project documentation must establish which volumes communicate at each state.
Build a state table instead of adding every maximum
Now construct an original example using the two double-acting cylinders above. Assume a separate single-acting actuator withdraws 4 L and an accumulator gains 3 L of oil at the maximum-demand state. These are assumed oil changes, not dimensions or pressure ratings.
The reference state has both double-acting cylinders retracted, the single-acting actuator at its low-oil position, the accumulator at its reference oil condition, and all relevant lines filled. Assume the maximum-demand combination is physically possible.
Maximum net withdrawal is:
1.909 + 4 + 3 = 8.909 L.
For a separate high-return shutdown state, assume the actuators and accumulator have returned to their reference oil condition. A specified line volume then drains back by 2 L. An independently established thermal allowance adds another 1.2 L to the reservoir balance in this state. This allowance is an illustrative input, not a universal expansion percentage.
Select a provisional reference fill V0 of 25 L:
| State | Net withdrawal relative to reference | Thermal correction | Reservoir quantity |
|---|---|---|---|
| Reference | 0 L | 0 L | 25 L |
| Maximum demand | +8.909 L | 0 L in this example | 16.091 L |
| High-return shutdown | −2 L | +1.2 L | 28.2 L |
Do not add the actuator return of 8.909 L to the reference 25 L again. Returning to the reference actuator state already restores the reservoir to 25 L before the additional drainback and thermal correction.
Likewise, do not subtract every possible component maximum if those positions cannot occur together. Document the reachable states, then find their extrema. The example assumes its listed states cover the inventory extremes; a real project must include other cold, hot, partial-stroke, service, and shutdown combinations where relevant.

Convert the result into fill levels and tank geometry
Suppose the preliminary design permits no less than 15 L of liquid for operating conditions and no more than 32 L for the reviewed high-level conditions. These are invented design inputs requiring engineering verification.
To cover the example's 8.909 L withdrawal and 3.2 L maximum increase, the reference fill must satisfy:
V0 ≥ 15 + 8.909 = 23.909 L
V0 ≤ 32 − 3.2 = 28.8 L
The provisional 25 L fill lies in that interval. Its lowest listed state is 1.091 L above the assumed minimum, and its highest listed state is 3.8 L below the assumed maximum. Those differences are arithmetic results, not recommended safety margins.
Consider a purely geometric rectangular tank with internal dimensions 0.5 m × 0.4 m × 0.2 m. Ignoring all internal displacement, its gross volume is 0.04 m³, or 40 L. Its horizontal area is 0.2 m².
The 15 L minimum corresponds to 75 mm liquid depth; 25 L corresponds to 125 mm; and 32 L corresponds to 160 mm. At the assumed maximum liquid quantity, 40 mm of height remains above the oil. This illustrates the distinction between gross capacity and liquid levels.
An actual tank needs correction for internal components, baffles, shape changes, unusable spaces, and installation attitude. Inlet submergence and return arrangements must be checked using the real geometry. Do not use these dimensions as a fabrication drawing.
Parker's reference guidance recognizes the need to accommodate returning cylinder oil and space for expansion. Its historical numeric rules are not adopted here as universal design values. Parker reservoir considerations, printed page 19. For catalog packages, use HPU reservoir size selection to compare the calculated requirement with supplier-defined limits.

Check air release, return flow, and inlet performance
Inventory capacity is necessary but does not establish fluid-handling performance. Determine peak return rates, their duration, entry locations, and the conditions at the pump pickup. Return flow can differ from pump delivery because of cylinder area ratios, accumulator discharge, and other circuit behavior.
For illustration, 25 L divided by a circulating flow of 20 L/min gives 1.25 minutes, or 75 seconds, of nominal turnover time. This is not a guaranteed residence time for every portion of the oil and is not an air-release acceptance criterion.
Internal flow may short-circuit between return and pickup. Fluid properties, bubble size, turbulence, temperature, and geometry affect separation. A simple time ratio cannot resolve those factors.
Rexroth's myCRO approach includes flow evaluation and application-dependent degassing measures. It supports evaluating the actual fluid path rather than choosing volume alone. No advertised reduction percentage is applied to this example. myCRO overview.
Also check inlet losses and fluid viscosity at relevant cold conditions. A large inventory cannot compensate for an unsuitable suction path. Noise and unstable behavior can have several causes, discussed in hydraulic power unit noise.
Separate thermal capacity from continuous cooling
Oil volume contributes to thermal storage. At a given net heat input, more thermal mass can reduce the rate of temperature rise. Long-term temperature, however, depends on the balance between heat generated and heat rejected.
Evaluate the duty cycle rather than substituting the motor nameplate power for heat load. Identify throttling losses, leakage, mechanical losses entering the fluid, and any external heat transfer. Check ambient conditions and the effectiveness of the installed cooler or other heat-rejection surfaces.
HYDAC's cooling tool separates inputs such as liquid flow, temperatures, power, and tank volume. No thermal simulation or cooler selection has been performed for the worked example. HYDAC Cool-IT.
The thermal expansion correction in the inventory table is also different from a cooling calculation. Expansion affects how much space the oil occupies; heat rejection determines whether the operating temperature remains acceptable.
Use supplier fluid-property data and a justified temperature range for expansion calculations. Include the relevant system oil and structural effects at the level of detail the application needs. Coordinate the result with motor and pump sizing and the complete thermal design.
Record assumptions and verify the design
Keep a calculation sheet with a row for each changing volume. Record geometry or supplier data, reference state, sign, amount, compatible operating states, temperature condition, and uncertainty. Label measured, calculated, and assumed values separately.
| Review item | Required record |
|---|---|
| Cylinder inventory | Dimensions, travel and circuit connections |
| Accumulator exchange | Approved oil-volume change and conditions |
| Line drainback | Which lines drain, when, and where their oil goes |
| Thermal correction | Fluid-property basis and relevant temperature states |
| Liquid-level limits | Geometry, attitude, inlet and high-level requirements |
| Final capacity | Internal displacement, usable range and verification evidence |
Verification should cover the relevant minimum and maximum states, return-flow events, approved attitudes, temperature conditions, and level-monitoring functions. Follow a reviewed commissioning plan with suitable controls for stored energy and moving loads.
Check that actual measured levels correspond to the documented reference state. If they differ, investigate filling, trapped air, undocumented volumes, or state assumptions before adjusting the design record.
Use pump, valve, and cylinder matching to review interactions. Tank wall strength, support, lifting provisions, fabrication quality, cleanliness, and applicable requirements remain separate engineering responsibilities. Passing the volume calculation does not release the tank for manufacture.
Preguntas frecuentes
Is there one hydraulic tank-size formula? A volume balance determines inventory needs, but final capacity also depends on liquid-level constraints, fluid handling, cooling, geometry, and application verification.
Does a double-acting cylinder withdraw its full cap-end volume? In the conventional same-reservoir circuit described here, simultaneous rod-end return reduces net withdrawal to rod displacement volume.
Should accumulator nameplate liters be added directly? No. Use the actual oil exchange for the relevant states, not nominal gas or vessel volume.
Is gross tank capacity the required initial oil fill? No. The fill must place every reviewed state within the permitted liquid range while preserving required space above the oil.
What if the cylinder dimensions are uncertain? Obtain identified drawings and specifications. The method in cylinder drawing review helps resolve stroke and geometry before they enter the inventory calculation.
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